Its an electromagnetic wave that decays exponentially the further it travels.
Science quiz
Started by
Guest_Mirai Naza
, Jun 04 2006 09:42 PM
981 replies to this topic
#802
Kiririn-shi
-
- Dragon's Elite
-
- 7,352 posts
Hanyaa~
Reputation: 2
Neutral
Posted 09 December 2006 - 05:21 PM
Nope, it's an attenuating wave you are describing, evanescent waves have a special characteristic.
#803
Guest_Маушта!!!
Guest_Маушта!!!
-
- Guest
Posted 09 December 2006 - 05:34 PM
An evanescent wave is a wave exhibiting exponential decay with distance.
#804
Kiririn-shi
-
- Dragon's Elite
-
- 7,352 posts
Hanyaa~
Reputation: 2
Neutral
Posted 09 December 2006 - 05:54 PM
Well, it's somehow the same answer as before...
#805
Guest_kwiksylver
Guest_kwiksylver
-
- Guest
Posted 10 December 2006 - 12:52 AM
If what the other people said is incorrect, the only thing I can add is that an evanescent wave is a wave that is reflected off of something with an angle greater to the critical angle so that complete internal reflection occurs.
#806
Guest_ShadowHobbit
Guest_ShadowHobbit
-
- Guest
Posted 10 December 2006 - 01:00 AM
This is kinda dumb... people can just look the answers up on the internet... it's not testing anything... POINTS were deducted for this post by Ody
#807
Kiririn-shi
-
- Dragon's Elite
-
- 7,352 posts
Hanyaa~
Reputation: 2
Neutral
Posted 10 December 2006 - 02:16 AM
kwiksylver is correct.278. Cite different patterns of interference? (2 points)Score board:Eärendil - IIRed Anvil - IIatomicknight - ICoatlicue - Ibasf11214 - 40SirAnthos - 4Eärendil - 2kwiksylver - 2NoFox - 2
#808
Guest_kwiksylver
Guest_kwiksylver
-
- Guest
Posted 10 December 2006 - 02:43 AM
I think there are 2 types of interference: destructive and constructive. Destructive is when waves are out of phase and constructive is when they are in phase.
#809
Guest_Vibronater
Guest_Vibronater
-
- Guest
Posted 10 December 2006 - 02:51 AM
Standing and Circular?My teacher wasn't great on Waves and the such...
#810
Kiririn-shi
-
- Dragon's Elite
-
- 7,352 posts
Hanyaa~
Reputation: 2
Neutral
Posted 10 December 2006 - 02:53 AM
RA is correct.280. What was the Michelson originally used for? (2 points)Score board:Eärendil - IIRed Anvil - IIatomicknight - ICoatlicue - Ibasf11214 - 40SirAnthos - 4Eärendil - 2kwiksylver - 2NoFox - 2Red Anvil - 2
#811
Guest_Vibronater
Guest_Vibronater
-
- Guest
Posted 10 December 2006 - 02:58 AM
To test for the existence of the ether.The medium that light passes through (I think so)
#812
Kiririn-shi
-
- Dragon's Elite
-
- 7,352 posts
Hanyaa~
Reputation: 2
Neutral
Posted 10 December 2006 - 03:01 AM
RA is correct.281. What is currently the main usage for the Michelson? (2 points)Score board:Eärendil - IIRed Anvil - IIatomicknight - ICoatlicue - Ibasf11214 - 40Red Anvil - 4SirAnthos - 4Eärendil - 2kwiksylver - 2NoFox - 2
#813
Guest_Vibronater
Guest_Vibronater
-
- Guest
Posted 10 December 2006 - 03:04 AM
Measuring the wavelength of light, for using the wavelength of a known light source to measure extremely small distances, and for investigating optical media. Again I learned that myself so...
#814
Guest_kwiksylver
Guest_kwiksylver
-
- Guest
Posted 10 December 2006 - 03:04 AM
It is used as an interferometer.
#815
Kiririn-shi
-
- Dragon's Elite
-
- 7,352 posts
Hanyaa~
Reputation: 2
Neutral
Posted 10 December 2006 - 03:06 AM
Both are correct.282. What does the Laplacian become in a complexe transformation? (3 points)Score board:Eärendil - IIRed Anvil - IIatomicknight - ICoatlicue - Ibasf11214 - 40Red Anvil - 6kwiksylver - 4SirAnthos - 4Eärendil - 2NoFox - 2
#816
Guest_basf11214
Guest_basf11214
-
- Guest
Posted 10 December 2006 - 08:26 PM
Does it become the Laplace-de Rham operator?
#817
Kiririn-shi
-
- Dragon's Elite
-
- 7,352 posts
Hanyaa~
Reputation: 2
Neutral
Posted 11 December 2006 - 02:32 AM
Nope, it's quite simple... it's a multiplication by anumber, but which?
#818
Guest_basf11214
Guest_basf11214
-
- Guest
Posted 11 December 2006 - 03:53 AM
Is it i ? That's the most obvious thing I can think of....and the most unlikely answer.
#819
Kiririn-shi
-
- Dragon's Elite
-
- 7,352 posts
Hanyaa~
Reputation: 2
Neutral
Posted 11 December 2006 - 04:26 AM
Not really. When you make a temporal derivative, using the complexe notation, you do equivalently a multiplication by i*t. Similarly, you can do a spatial derivation and multiply by [insert something]... and similarly for the Laplacian.
#820
Eärendil
-
- Active Member
-
- 621 posts
Dragon
Reputation: 0
Neutral
Posted 11 December 2006 - 02:44 PM
I think it is i*c
He saw the Mountain silent rise
where twilight lies upon the knees
of Valinor, and Eldamar
beheld afar beyond the seas.
#821
Kiririn-shi
-
- Dragon's Elite
-
- 7,352 posts
Hanyaa~
Reputation: 2
Neutral
Posted 11 December 2006 - 04:05 PM
Well, 2 mistakes in your answer:1. It's not c.2. Laplacian is a second order derivative and your multiplication is only a first order.
#823
Kiririn-shi
-
- Dragon's Elite
-
- 7,352 posts
Hanyaa~
Reputation: 2
Neutral
Posted 12 December 2006 - 05:27 AM
Err... j is just the imaginary number, it's exactly the same as i except that in physics, i is already often used so that j replaces it as to avoid confusion.
#824
Guest_Vibronater
Guest_Vibronater
-
- Guest
Posted 12 December 2006 - 05:29 AM
I meant equals 0...Give us a break, it's advanced calculas :PI know like 10 % of what I need for it...
#825
Kiririn-shi
-
- Dragon's Elite
-
- 7,352 posts
Hanyaa~
Reputation: 2
Neutral
Posted 12 December 2006 - 05:33 AM
Ok... you just multiply by -k².283. How is k defined? (2 points)Score board:Eärendil - IIRed Anvil - IIatomicknight - ICoatlicue - Ibasf11214 - 40Red Anvil - 6kwiksylver - 4SirAnthos - 4Eärendil - 2NoFox - 2
